thanks

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Added by CaptainBlack

Please do not delete your questions after they have been solved.

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- May 21st 2006, 07:27 PMJohnSenaNeed solutions for some easy calc problems
thanks

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Added by CaptainBlack

Please do not delete your questions after they have been solved.

It makes it more difficult for someone else to benefit from the

solutions. - May 21st 2006, 07:31 PMThePerfectHackerQuote:

Originally Posted by**JohnSena**

Divide sides by 25,

Take, logarithm

Thus, the exponent "comes down"

Thus,

- May 21st 2006, 07:34 PMThePerfectHackerQuote:

Originally Posted by**JohnSena**

Divide by 2,

Divide by thus,

Divide by four,

Take natural logarithm of both sides,

Thus,

- May 21st 2006, 07:57 PMJohnSena
damn that was quick thanks

still confused on how to figure out part b and the other problems though, if anybody could help with those that'd be awesome - May 21st 2006, 11:00 PMCaptainBlackQuote:

Originally Posted by**JohnSena**

So the population satisfies this differential equation:

,

which has solution:

.

Now we are told that the population grows by per year, so

after one year the population is times its original value so:

,

so: (thats a natural log by the way).

hence:

. - May 21st 2006, 11:03 PMCaptainBlackQuote:

Originally Posted by**JohnSena**

the differential equation:

,

which has solution:

,

plugging in the given initial population gives:

.

RonL - May 21st 2006, 11:17 PMCaptainBlackQuote:

Originally Posted by**JohnSena**

population is proportional to the existing population. Hence the population

satisfies the diffrenetial equation:

,

which has solution:

Now we are told that the population doubles in 8 hours so:

,

so: , or: .

Therefore:

.

Now at time the population is 5 times its original value so:

,

so:

or laking logs:

,

or:

RonL - May 26th 2006, 08:15 AMCaptainBlackQuote:

Originally Posted by**JohnSena**

It makes it more difficult for someone else to benefit from the

solutions.

RonL