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Math Help - homogeneous ODE

  1. #1
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    homogeneous ODE

    How do we get the root values for y''''-4y'''+7y''-6y+2y=0..?
    Is it done by long division and we need to assume that one of the root is always = 1 by trial and error?
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  2. #2
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    Quote Originally Posted by ashes View Post
    How do we get the root values for y''''-4y'''+7y''-6y+2y=0..?
    Is it done by long division and we need to assume that one of the root is always = 1 by trial and error?
    Trial and error. In fact, (x - 1)^2 is a factor. The remaining (quadratic) factor is x^2 - 2x + 2.
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  3. #3
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    So i got y=(A+Bx)e^x +e^x (Ccosqx + Dsinqx) as my general solution..thats how it should look right?
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  4. #4
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    Quote Originally Posted by ashes View Post
    So i got y=(A+Bx)e^x +e^x (Ccosqx + Dsinqx) as my general solution..thats how it should look right?
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