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Math Help - Sequence and bounds

  1. #1
    Member akhayoon's Avatar
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    Sequence and bounds

    a_{n}=\frac{n}{n+1}

    is bounded below by \frac{1}{2}

    and above by 1

    here they mean the greatest lower bound and least upper bound..

    so I don't understand how u could find these bounds by simply being given
    a_{n}=\frac{n}{n+1}

    can some one please explain to me how this work?
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  2. #2
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    Sequences I believe take integer values of n greater than 0. Since this sequence can be written as 1 - 1/n it is clearly increasing, so the smallest value is when n=1, and largest as n tends to infinity, is 1.
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