Hi everyone. Got stuck again. Solved it for when x-> infinity but cant seem to get it for when x->0. Appreciate any help at all!
lim$\displaystyle
\frac{3^{x}+ln{(absx)}}{x^5+x^4}
$
x->0
Thanks!
You could try expanding and see what you come up with. Sometimes it makes it easier to see. Since x-->0, you shouldn't have to worry about an absolute value.
$\displaystyle \lim_{x\rightarrow{0}}\frac{3^{x}+ln(x)}{x^{5}+x^{ 4}}$
$\displaystyle =\lim_{x\rightarrow{0}}\left[\frac{ln(x)}{x+1}-\frac{ln(x)}{x}+\frac{ln(x)}{x^{2}}-\frac{ln(x)}{x^{3}}+\frac{ln(x)}{x^{4}}+\frac{3^{x }}{x+1}-\frac{3^{x}}{x}+\frac{3^{x}}{x^{2}}-\frac{3^{x}}{x^{3}}+\frac{3^{x}}{x^{4}}\right]$