1+a(a+1)+a(a+1)(a-2)(a+3)+a(a+1)(a-2)(a+3)(a-4)+a(a+1)(a-2)(a+3)(a-4)(a+5) what can be a general summation could be written in the form
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a = first number in sequence r = ratio Hope that helps.
Originally Posted by mrbuttersworth a = first number in sequence r = ratio Hope that helps. How did you get that result? This is not a geometric series. -Dan
oh wow, I apologize, I read that one too quickly. Well in that case, I'm stumped. Sorry about that first response. That's a general solution for the sum of a geometric series.
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