evaluate integral for interval between x=0 and x=1 INT: (x^2)(1+x)^0.5 dx thanks
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Originally Posted by daaavo evaluate integral for interval between x=0 and x=1 INT: (x^2)(1+x)^0.5 dx thanks Try a u sub let then and using the above and substition expanding the binomial we get... From here it is off to the races...
Originally Posted by daaavo evaluate integral for interval between x=0 and x=1 INT: (x^2)(1+x)^0.5 dx After substitution the integral becomes Now this is routine. After some straightforward calculations your integral is equal to
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