almost got a solution to a differential equation, but wondering if anyone could help me tidy things up...
I have (int 1/(1+v^2)dv - (int v/(1+v^2)dv = ln(x)+C
which gives
arctan(v)-1/2ln(1+v^2)=ln(x)+C
Iam using v=y/x
is there any way of solving for y?? I thought of using exp but itll probz end up messy, what would be the general solution in this case?
another prob if anyones up for it,
an integral left from a dif eq...
int 1+v/((v-1)^2) dv .....