Help with improper integrals

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March 6th 2008, 08:57 AM
luckeyduck

Help with improper integrals

the integral from neg. infinity to 6 of re^(r/3)

thanks!
March 6th 2008, 09:09 AM
TheEmptySet

$\int_{-\infty}^6re^{\frac{r}{3}}dr=\lim_{a\to-\infty}\int_a^6rd^{\frac{r}{3}}=$

$\lim_{a\to-\infty}3re^{\frac{r}{3}}-9e^{\frac{r}{3}}|_{a}^{6}$

I used integration by parts

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