1. ## Inverse Derivatives!

Find the derivative of the function below.

h(w) = w^3ln(6w)

i keep coming up with the wrong answer...can someone tell me where im messing up

thanks

mathlete

2. Originally Posted by mathlete
Find the derivative of the function below.

h(w) = w^3ln(6w)

i keep coming up with the wrong answer...can someone tell me where im messing up

thanks

mathlete
First off, is the function this: $h(w) = w^3ln(6w)$

or this? $h(w) = w^{3ln(6w)}$

3. it's exactly what i wrote,

h(w) = w^3(ln(6w))

so its the first one you wrote down

4. Originally Posted by mathlete
it's exactly what i wrote,

h(w) = w^3(ln(6w))

so its the first one you wrote down
In that case, you need to practice the product rule: $h=fg; h'=f'g+fg'$

$h(w) = w^3(ln(6w))$

$h'(w) = 3w^2(ln(6w)) + \frac{6w^3}{6w}$

$h'(w) = 3w^2(ln(6w)) + w^2$

It seems you either had a typo, or you misread something when applying the first term of the product rule.

5. ahhh, yeah stupid mistake, i used the chain rule to get the derivative of
ln(6w) which was more than i needed to do. Then i was still thinking chain rule and pluged in ln(6w) for w into 3w^2. thanks for the help...