Originally Posted by

**larson** Hey guys, I just wanted to make sure that I did this question correctly:

The fourth-order Taylor polynomial for $\displaystyle f(x) = \frac {1}{x}$ based at $\displaystyle x = 1$ is $\displaystyle P4(x) = 1 - (x - 1) + (x - 1)^2 - (x - 1)^3 + (x - 1)^4$. Find the fourth-order Maclaurin polynomial for $\displaystyle g(x) = \frac {1}{(1 + x)}$

So all I did was place (1 + x) wherever I see an x up in the original function, which would mean...

$\displaystyle 1 - ((1 + x)-1) + ((1 + x)-1)^2 - ((1 + x) - 1)^3 + ((1 + x) -1)^4$

which would then mean the final answer is:

$\displaystyle 1 - x + x^2 - x^3 + x^4$ right?