is this integrals correct?
1/y+t^2 (dt) = arctan t
what is the correct integral of 1 + y^2?
thanks!
$\displaystyle \int \frac{1}{y} + t^2 dt = \frac{t}{y} + \frac{t^3}{3} + C$
$\displaystyle \int 1 + y^2 dy = y + \frac{y^3}{3} + C$
I believe Dan answered what you wanted, but I listed these just in case.
Nevertheless, do not forget adding a constant in for indefinite integrals! $\displaystyle + C$!