intergrate (2x-3)/((9-x^2)^1/2) dx
Believe I need to break this down into 2x/(9-x^2)^1/2dx - 3/(9-x^2)^1/2 dx. I cant afford to not undertstand these problems though.
What you need is a sneaky little substitution, when you have integrals similar to this all you need to know is the trig identity (and the similar cosh identity is useful for others with - instead of +). You should notice that with this substitution (try x proportional to cos) you can get the whole root to cancel with the other contribution (remember if you sub x=f(y) then you must replace dx=f'(y)dy) which gives a nice easy integral...
If you have any problems with this lot let me know and I'll give you a few more clues (or if you want to check your answer i've got it on my scratch pad next to me) but I don't want to spoil your fun of learning this stuff. Besides, its fun to play the sadist who used to make me work things out for myself!!!