Intergrate (2x^2+4x+22) / (x^2+2x+10) dx
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Hello, Bust20001 Divide: . . . . . . . . . . .
Originally Posted by Bust2000 Intergrate (2x^2+4x+22) / (x^2+2x+10) dx . You should have better luck with this form .....
Originally Posted by Bust2000 Intergrate (2x^2+4x+22) / (x^2+2x+10) dx When your integrand is in the form , where are both polynomials, and the order of is greater or equal to the order of ; always try long division first before integrating. Here we have: Now, use substitution (let ) we got:
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