intergrate (2x-3)/(x^2+16) dx

Question is intergrate by partial fractions if so what am I not seeing complete the square in the denominator? Thanks for Checking out question people.

Printable View

- Mar 3rd 2008, 06:13 PMBust2000Intergrate
intergrate (2x-3)/(x^2+16) dx

Question is intergrate by partial fractions if so what am I not seeing complete the square in the denominator? Thanks for Checking out question people. - Mar 3rd 2008, 06:16 PMJhevon
- Mar 3rd 2008, 06:24 PMBust2000Question
Can you give me a little deminstration of what you are saying you are saying do a u substition of intergral uv -intergral v du. Sorry I need to work with my equation converter more it doesnt recognize intergrals still. Thanks

- Mar 3rd 2008, 06:56 PMJhevon
you are mixing this up with integration by parts, that is not what i am talking about. i am saying you must do integration by substitution. please look up this method, and try not to confuse the two

Quote:

Sorry I need to work with my equation converter more it doesnt recognize intergrals still. Thanks

now, does that integral look familiar? it should. now do a substitution to see. - Mar 3rd 2008, 07:18 PMSoroban
Hello, Bust2000!

Quote:

Intergrate: .

The first integral is:.

. . Let

. . Substitute: .[

And the second integral is of the form: .