f '(x) = x^2(x+1)^3 Thanks for the help
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Originally Posted by acburn_22 f '(x) = x^2(x+1)^3 Thanks for the help What you want to find is $\displaystyle \int x^2 (x+1)^3 ~ dx $. The most straightforward way to do this is $\displaystyle x^2(x+1)^3 = x^5 + 3x^4+3x^3+x^2$. And do the integral from there.
Thanks, that made it alot easier!
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