# Math Help - find solution of equation

1. ## find solution of equation

Hello, just another equation sorry about the hassle..
Find the solution
(x+y)y'=10y-x which satisfies y(3)=2

not sure how to go about doing this..

2. $y' = \frac{{3y - x}}
{{x - y}} = \frac{{\dfrac{{3y}}
{x} - 1}}
{{1 - \dfrac{y}
{x}}}.$

Now consider $y=xz.$