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Thread: find solution of equation

  1. March 2nd 2008, 01:44 PM #1
    biffer
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    find solution of equation

    Hello, just another equation sorry about the hassle..
    Find the solution
    (x+y)y'=10y-x which satisfies y(3)=2

    not sure how to go about doing this..
    Last edited by biffer; March 4th 2008 at 06:08 AM.
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  2. March 2nd 2008, 01:55 PM #2
    Krizalid
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    y' = \frac{{3y - x}}<br /> {{x - y}} = \frac{{\dfrac{{3y}}<br /> {x} - 1}}<br /> {{1 - \dfrac{y}<br /> {x}}}.

    Now consider y=xz.
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