# find solution of equation

• Mar 2nd 2008, 02:44 PM
biffer
find solution of equation
Hello, just another equation sorry about the hassle..
Find the solution
(x+y)y'=10y-x which satisfies y(3)=2

not sure how to go about doing this..
• Mar 2nd 2008, 02:55 PM
Krizalid
$y' = \frac{{3y - x}}
{{x - y}} = \frac{{\dfrac{{3y}}
{x} - 1}}
{{1 - \dfrac{y}
{x}}}.$

Now consider $y=xz.$