$\displaystyle \int \frac{t^{2.7}}{4+t^3}{dt}$ I've tried using substitution or integration by parts, but I can't figure out how to pick what U equals, and I don't really know where to start.
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just do long division (it's a little hard to wrute this in latex) $\displaystyle \frac{{t^{27} }} {{4 + t^3 }} = t^{24} - 4t^{21} + 16t^{18} \cdots $
Originally Posted by Peritus just do long division (it's a little hard to wrute this in latex) $\displaystyle \frac{{t^{27} }} {{4 + t^3 }} = t^{24} - 4t^{21} + 16t^{18} \cdots $ That one is easy. For this one, though, the exponent is 2.7, not 27. -Dan
Originally Posted by topsquark That one is easy. For this one, though, the exponent is 2.7, not 27. -Dan in that case there is no simple integral, wolfram integrator gives an answer which includes the hypergeometric function.
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