v = 3 sin (u) - 10tan (u) + 101n (u) + 2e^u
the answer i got was
3cos (u) - 10/cos^2 (u) + 101/u + 2ue^u-1
maybe not right stuck with what to do on the -10tan and the last part
i did use ^ on the 2e ^ u is supposed to read 2e to the power of u
the n is just in the question it reads +101n (u) but im not 100% sure what to do with that
the e^u yeh that should be 2e^u after readin my notes again.
3cos (u) - 10/cos^2 (u) + 101/u + 2e^u
big question mark on the 101/u part however
for 101n (u), are we to assume it looks like ? in that case, it's just using the power rule...
wait did you mean , as in the natural log of u? it is not a 1, it is a lower case L!
so, if you have the derivative is
and as i said, write instead of , it looks nicer
the rest are ok