v = 3 sin (u) - 10tan (u) + 101n (u) + 2e^u
the answer i got was
3cos (u) - 10/cos^2 (u) + 101/u + 2ue^u-1
maybe not right stuck with what to do on the -10tan and the last part
the derivative of $\displaystyle e^x$ is $\displaystyle e^x$
the derivative of a function of the form $\displaystyle a^x$, where $\displaystyle a>0$ is a constant and $\displaystyle x$ is our variable, is $\displaystyle a^x \ln a$
what is 101n (u) ?
what is the n? are there any powers here? (you should use ^ to indicate powers, so we know what you're talking about)
i did use ^ on the 2e ^ u is supposed to read 2e to the power of u
the n is just in the question it reads +101n (u) but im not 100% sure what to do with that
the e^u yeh that should be 2e^u after readin my notes again.
3cos (u) - 10/cos^2 (u) + 101/u + 2e^u
big question mark on the 101/u part however
for 101n (u), are we to assume it looks like $\displaystyle 101nu$? in that case, it's just using the power rule...
wait did you mean $\displaystyle \ln u$, as in the natural log of u? it is not a 1, it is a lower case L!
so, if you have $\displaystyle 10 \ln u$ the derivative is $\displaystyle \frac {10}u$
and as i said, write $\displaystyle \sec^2 x$ instead of $\displaystyle \frac 1{\cos^2 x}$, it looks nicer
the rest are ok