Let f(x)= (x-(1/2))^2 + 3, 0<= x <= 1. If the interval [0,1] is partitioned into 4 subintervals of equal length, then what is the value of the smallest Riemann sum for f(x) and this partition?
Let f(x)= (x-(1/2))^2 + 3, 0<= x <= 1. If the interval [0,1] is partitioned into 4 subintervals of equal length, then what is the value of the smallest Riemann sum for f(x) and this partition?
they want you to do the lower Riemann sum
so you would partition the interval into [0,1/4], [1/4,1/2], [1/2, 3/4], and [3/4,1]
in each of these intervals, find the point that makes the smallest, and then use those points as your 's in the formula