# Math Help - Finding tanget line to a graph at given point

1. ## Finding tanget line to a graph at given point

Find the equation of the tangent line to the graph of the given function at the given value of x,
F(x)=((x^2)+28)^(4/5), x=2

2. $f(x) = (x^2 + 28)^{\frac{4}{5}}$

$f'(x) = \frac{4}{5} 2x (x^2 + 28)^{- \frac{1}{5}}$ by the chain rule

$f'(2) = \frac{16}{5} (32)^{- \frac{1}{5}}$
$f'(2) = \frac{8}{5}$

the rest is pretty routine

$y - f(2) = f'(2) ( x - 2)$

can you finish that off ?