x=y^2-3ln(2y)

a) show that dy/dx = y/(2y^2-3)

b) find equation for tangent to curve where y=1/2

give answer in form ax+by+c=0 where a, b, c are all integers

Have done a) cannot do b) can someone help me please?

Should have said, can do b), but my answer is never an integer, can someone see wot i am doing wrong. i get x=1/4 and dy/dx = -1/5 are these wrong?