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Math Help - Intergration Help!

  1. #1
    Member looi76's Avatar
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    Intergration Help!

    Question:
    Find the value of the infinite integral:

    \int^\infty_2 \frac{6}{x^4}dx

    Attempt:
    \int^\infty_2 \frac{6}{x^4}dx
    = 6x^-4
    = \frac{6x^{-4+1}}{-4+1}
    = \frac{6x^{-3}}{-3}
    = -2x^{-3}
    = [ -2x^{-3} ]^{\infty}_2
    = [-2(\infty)^{-3} ] - [-2(2)^{-3} ]
    = ?

    If there was a number in the infinity position then I would be able to solve it, but with the infinity there. I need help!
    Last edited by looi76; March 1st 2008 at 12:35 AM.
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  2. #2
    Senior Member Peritus's Avatar
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  3. #3
    Member looi76's Avatar
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    I didn't understand anything from wikipedia. Can you please explain?
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  4. #4
    Senior Member Peritus's Avatar
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    Have you studied limits?
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  5. #5
    Member looi76's Avatar
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    No, thats the problem. I missed the class
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