Hello, I was hoping someone could pick off where I went wrong on these two questions. As far as I can tell I have the right answers but the program I am plugging the answers into says nay. Not sure on how to do the integral symbol on this forum so just assume it is there.
1) Integrate by partial fractions
Using the partial fractions I was able to change it to
which is so far correct according to the program (in bx+c on the top of the second fraction the c is 0)
So I am down to integrating
and
. Using the natural log rule the first I figure is 2ln(x+1) and the second I solved using
and getting 1/2du=x. The 1/2 comming outside of the integral it leaves 1/2 the integral of du/u, which is 1/2ln(u), which then gives you -4(1/2)ln(x^2+4) as the second integral.
Mr F says: NO! First of all, it's a standard form: . As to why and where your substitution goes wrong, see below.
So I figured
should be the answer, but it comes back as wrong and I am running out of attempts with no clue where I am wrong on this.
[snip]