Need help with....

**ArmiAldi** · February 28th 2008, 03:55 PM

If anyone can help me with:
Find the derivative

x5
y = e Inx

Thank You

y=e^{x^5}ln(x)

**TheEmptySet** · February 28th 2008, 04:04 PM

Originally Posted by ArmiAldi

If anyone can help me with:
Find the derivative

x5
y = e Inx

Thank You

If you mean

$y=e^{5x}ln(x)$

the product rule gives us...

$5xe^{5x}ln(x)+\frac{1}{x}e^{5x}=e^{5x}\left(5xln(x )+\frac{1}{x}\right)=$

$e^{5x}\left(\frac{5x^2ln(x)+1}{x^2}\right)$

**TheEmptySet** · February 28th 2008, 04:06 PM

If you hover over equations with you cursor you can see the code used to generate them. Also if you double click on an equation it will open the code for view in a seperate box.

It makes reading and writing equations alot easier.

Good luck.

**quarks** · February 28th 2008, 04:09 PM

Please use the ^ sign to show powers. Otherwise, it can get confusing. =)

As a general rule, when deriving:

$\frac{d}{dx}\ x^n$ = $n x^{n-1}$

So use that to find the derivative of $x^5$ .

If your second derivative is $e^{lnx}$ , then you can simplify it by remembering that $e^{lnx}\ =\ x$

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