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Thread: integration helpppppp

  1. February 26th 2008, 12:46 PM #1
    simsima_1
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    integration helpppppp

    <br /> <br /> \int sin{^2}(x)cos{^4}(x)<br /> <br />

    i did it all the way to

    <br /> <br /> \frac {1}{8} \int sin{^2}(2x)+sin{^2}(2x)cos(2x)<br /> <br />

    then i split it up and have no idea what happens next...
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  2. February 26th 2008, 12:49 PM #2
    Jhevon
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by simsima_1 View Post
    <br /> <br /> \int sin{^2}(x)cos{^4}(x)<br /> <br />

    i did it all the way to

    <br /> <br /> \frac {1}{8} \int sin{^2}(2x)+sin{^2}(2x)cos(2x)<br /> <br />

    then i split it up and have no idea what happens next...
    hopefully your last line is right, i didn't check. it looks a little fishy to me.

    anyway, note that \sin^2 2x = \frac {1 - \cos 4x}2. so you can easily integrate the first part

    for the second part, use the substitution u = \sin 2x
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