FInd the area bewteen the curves $\displaystyle x=y^2$ and the RIGHT semi-circle $\displaystyle x^2+y^2=2$
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The equations are, $\displaystyle x=y^2$ $\displaystyle x=\sqrt{2-y^2}$ Set up the integral, find the bounds.. $\displaystyle \int^{1}_{-1} \int^{\sqrt{2-y^2}}_{y^2}~dx~dy$
i havent learned double integrals.....so how do you do it using single integrals....or is there another way?
Originally Posted by polymerase i havent learned double integrals.....so how do you do it using single integrals....or is there another way? $\displaystyle \int_{-1}^1 (\sqrt{2 - y^2} - y^2)~dy$ is fine
For this particular question, my professor said, "There is a very fasy (altervative, not double integral) way to do this problem! Think about it!" of course he doesn't tell us! Any idea what the "very fast" way is?
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