Results 1 to 2 of 2

Math Help - [SOLVED] Limits. LIMITS!

  1. #1
    spinscent
    Guest

    Question [SOLVED] Limits. LIMITS!

    lim x --> 0

    (1/2+x) - (1/2)
    _____________
    x


    . . . I know the answer's -1/4, I just don't know how to get there.

    I'm not really even sure why it's confusing me. I just got done with a chapter about limits... Maybe the x's in both numerator and denominator are killing me..?

    I know I can't substitute. Gwah!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by spinscent View Post
    lim x --> 0

    (1/2+x) - (1/2)
    _____________
    x


    . . . I know the answer's -1/4, I just don't know how to get there.

    I'm not really even sure why it's confusing me. I just got done with a chapter about limits... Maybe the x's in both numerator and denominator are killing me..?

    I know I can't substitute. Gwah!
    do you mean \lim_{x \to 0} \frac {\frac 1{2 + x} - \frac 12}x? if so, use parenthese!

    there are not many options here. combine the fractions in the numerator.

    \Rightarrow \lim_{x \to 0} \frac {\frac {2 - 2 - x}{2(2 + x)}}x = \lim_{x \to 0} \frac {-x}{2(2 + x)} \cdot \frac 1x

    now what?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 7th 2009, 07:53 AM
  2. [SOLVED] limits
    Posted in the Calculus Forum
    Replies: 2
    Last Post: July 28th 2009, 08:05 PM
  3. [SOLVED] limits
    Posted in the Differential Geometry Forum
    Replies: 3
    Last Post: April 23rd 2009, 09:19 AM
  4. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 4
    Last Post: March 26th 2009, 07:25 PM
  5. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 3rd 2009, 08:13 PM

/mathhelpforum @mathhelpforum