Hello guys, I've got a math quiz tomorrow. My professor only uses previous homework problems that he assigns so I'm just going over all of the problems in the book that he assigned, lol. I'm having trouble with this question:

For the following problem, use integration by parts with the suggested u and dv to find the antiderivative.

$\displaystyle

{\int_{}\frac{lnx}{x^2}} dx

$

So... find the antiderivitive of: (lnx/x^2) dx ... u = lnx dv = (x^-2)dx

I get this far:

u = lnx

du/dx = 1/x

du = 1/x dx

dv = x^-2dx

dv/dx = x^-2

v = x^-1/1

So... u * v - integral (v * du)

lnx * x^-1/1 - integral (x^-1/1 * 1/x) dx