Given that y = X^x , x>0, y>0, by taking logs, show that

dy/dx = (X^x)(1+lnx)

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- February 24th 2008, 07:18 AMStylis10logarithms, confusing
Given that y = X^x , x>0, y>0, by taking logs, show that

dy/dx = (X^x)(1+lnx) - February 24th 2008, 07:29 AMTheEmptySet
- February 24th 2008, 07:31 AMearboth