1. ## Implicit Differentiation

Is this correct? If not, can you tell me where my mistake is?

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Question: Differentiate $\frac{x^2}{16} - \frac{y^2}{9} = 1$ With respect to $x$.

My Answer: $\frac{2x}{16} - \frac{2y}{9} \frac{\mathrm{d}y}{\mathrm{d}x} = 0$

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$\frac{{dy}}{{dx}} = \frac{{9x}}{{16y}}$