ok i need some help with this one... h(x) = x^5+1/(9x) i know first you have to make it so you have powers, but how would you do that for 1/(9x)...thanks mathlete
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$\displaystyle \frac{1}{x^n} = x^{-n}$ So, $\displaystyle \frac{1}{9x} = \frac{1}{9}\cdot \frac{1}{x} = \frac{1}{9}\cdot x^{-1}$
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