ok i need some help with this one...

h(x) = x^5+1/(9x)

i know first you have to make it so you have powers, but how would you do that for 1/(9x)...thanks

mathlete

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- Feb 22nd 2008, 08:53 AMmathletepower rule derivatives
ok i need some help with this one...

h(x) = x^5+1/(9x)

i know first you have to make it so you have powers, but how would you do that for 1/(9x)...thanks

mathlete - Feb 22nd 2008, 09:10 AMwingless
$\displaystyle \frac{1}{x^n} = x^{-n}$

So,

$\displaystyle \frac{1}{9x} = \frac{1}{9}\cdot \frac{1}{x} = \frac{1}{9}\cdot x^{-1}$