1. ## Integration

Hopefully, I attached the following problem.

I let u.doc

2. Originally Posted by kid funky fried
Hopefully, I attached the following problem.

I let u.doc
the answers are equivalent. you did nothing wrong.

$\displaystyle \frac 2{\sqrt{2}} = \sqrt{2}$. then just distribute the minus sign

3. Originally Posted by Jhevon
$\displaystyle \frac 2{\sqrt{2}} = \sqrt{2}$.
Might help to think of it like this:
$\displaystyle \frac 2{\sqrt{2}}~~ = ~~\frac {2^1}{2^{1/2}} ~~= ~~2^{(1-1/2)}~~ = ~~2^{1/2}~~ =~~ \sqrt{2}$

4. Originally Posted by angel.white
Might help to think of it like this:
$\displaystyle \frac 2{\sqrt{2}}~~ = ~~\frac {2^1}{2^{1/2}} ~~= ~~2^{(1-1/2)}~~ = ~~2^{1/2}~~ =~~ \sqrt{2}$
My preference $\displaystyle \frac{2}{\sqrt{2}} = \frac{\sqrt{2} \times \sqrt{2}}{\sqrt{2}}$ and then cancel the obvious common factor.

5. Originally Posted by mr fantastic
My preference $\displaystyle \frac{2}{\sqrt{2}} = \frac{\sqrt{2} \times \sqrt{2}}{\sqrt{2}}$ and then cancel the obvious common factor.
Thats another good way. I personally prefer to deal exclusively with fractions, I seem to see things quicker. And whenever I have to convert between fractions and crazy roots, I have to stop and think about it...

Of course, Jhevon helped me out with that one. (the power is a flower and the roots go underground)

6. thx for all your help.
it seems when i looked at angel.white's reply i understood immediately.
my wife, on the other hand, chose to do it like mr fantastic which took me about a minute to fully understand.
thx again!