Okay I haven't used to reduction formula a lot so I'm not sure if I did it correctly

$\displaystyle 64( \frac{-1}{3}sin^{2}(u)cos(u) + \frac{2}{3} \int sin du) $

$\displaystyle 64( \frac{-1}{3}sin^{2}(\frac{pi}{3})cos(\frac{pi}{3}) - sin^{2}(0)cos(0) + \frac{2}{3} ( \frac{1}{2} - \frac{pi}{2} )$

$\displaystyle 64(( (\frac{-1}{3}) (\frac{3}{4})(\frac{1}{2}) - \frac{pi}{2}) + \frac{2}{3} (\frac{1}{2} - \frac{pi}{2})$

I then simplify it to

$\displaystyle 64( \frac{-8 - 23pi}{24}) $

not sure if it's right...