Integral

**slevvio** · February 21st 2008, 01:43 AM

$\int\frac{xdx}{1+x^4}$ .

How do I integrate this? Thanks for any help.

**slevvio** · February 21st 2008, 01:53 AM

Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

$\int\frac{x}{1+(x^2)^2}dx$ Let $u = x^2$ and so $du=2xdx$

$\int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2}$ which is easily solved.

**topsquark** · February 21st 2008, 08:43 AM

Originally Posted by slevvio

Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

$\int\frac{x}{1+(x^2)^2}dx$ Let $u = x^2$ and so $du=2xdx$

$\int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2}$ which is easily solved.

Good job!

-Dan

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