1. ## Integral

$\int\frac{xdx}{1+x^4}$.

How do I integrate this? Thanks for any help.

2. Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

$\int\frac{x}{1+(x^2)^2}dx$ Let $u = x^2$ and so $du=2xdx$

$\int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2}$ which is easily solved.

3. Originally Posted by slevvio
Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

$\int\frac{x}{1+(x^2)^2}dx$ Let $u = x^2$ and so $du=2xdx$

$\int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2}$ which is easily solved.
Good job!

-Dan