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Math Help - Integral

  1. #1
    Senior Member slevvio's Avatar
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    Integral

    \int\frac{xdx}{1+x^4}.

    How do I integrate this? Thanks for any help.
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  2. #2
    Senior Member slevvio's Avatar
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    Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

    \int\frac{x}{1+(x^2)^2}dx Let  u = x^2 and so du=2xdx

    \int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2} which is easily solved.
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by slevvio View Post
    Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.

    \int\frac{x}{1+(x^2)^2}dx Let  u = x^2 and so du=2xdx

    \int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2} which is easily solved.
    Good job!

    -Dan
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