$\displaystyle \int\frac{xdx}{1+x^4}$.
How do I integrate this? Thanks for any help.
Haha, as usual I solve it within a few seconds of posting a question. Here is the solution if anyone is interested.
$\displaystyle \int\frac{x}{1+(x^2)^2}dx$ Let $\displaystyle u = x^2$ and so $\displaystyle du=2xdx$
$\displaystyle \int\frac{x}{1+(x^2)^2}dx=\frac{1}{2}\int\frac{[2xdx]}{1+(x^2)^2}=\frac{1}{2}\int\frac{du}{1+u^2}$ which is easily solved.