Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.9pi .

Printable View

- Feb 20th 2008, 09:33 AMwaite3please help involves the area of an integral
Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.9pi .

- Feb 20th 2008, 09:40 AMJhevon
- Feb 20th 2008, 09:50 AMwaite3
the sin function is the top and we get 6.877, yet the online program for submission being used is saying that that answer is incorrect, whereabouts would my error be lying? thanks for the help

- Feb 20th 2008, 11:45 AMxifentoozlerix
why dont you graph the two functions? you will see why your answer is wrong.

hint: $\displaystyle cos(0)=1$ while $\displaystyle sin(0)=0$