Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.9pi .

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- February 20th 2008, 10:33 AMwaite3please help involves the area of an integral
Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.9pi .

- February 20th 2008, 10:40 AMJhevon
- February 20th 2008, 10:50 AMwaite3
the sin function is the top and we get 6.877, yet the online program for submission being used is saying that that answer is incorrect, whereabouts would my error be lying? thanks for the help

- February 20th 2008, 12:45 PMxifentoozlerix
why dont you graph the two functions? you will see why your answer is wrong.

hint: while