1. ## Related Rates

If the volume of a cube is increasing at $24 in^3/min$ and the surface area of the cube is increasing at $12in^2/min$
, what is the length of each edge of the cube?
A. 2
B $2 \sqrt{2}$
C. $12^{1/3}$
D. 4
E. 8

This is what I know:
Dv/dt= 24
and DSA/dt= 12

$v= s^3$
SA= 3s...I think

So,
Dv/dt= 3s ds/dt
dSA/dt= 2 ds/dt

Ds/dt= $\frac{dv/dt}{3s}$

Now what?

Thanks!

2. Surface Area of a Cube is $6s^{2}$.