Would I use Partial Fractions for this integral? I'm not sure what to do. $\displaystyle \frac{1}{(x+1)(x+3)}dx$
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Originally Posted by killasnake Would I use Partial Fractions for this integral? I'm not sure what to do. $\displaystyle \frac{1}{(x+1)(x+3)}dx$ yes. use partial fractions. write $\displaystyle \frac 1{(x + 1)(x + 3)} = \frac A{x + 1} + \frac B{x + 3}$ now find A and B, similar to how i told you to in your last thread
okay cool thank you!
Do not use partial fraction. $\displaystyle \frac{1}{(x+1)(x+3)} = \frac{1}{2}\cdot \frac{(x+3) - (x+1)}{(x+1)(x+3)} = \frac{1}{2(x+1)} - \frac{1}{2(x+3)}$.
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