I need help with this Partial Fraction, I don't know how to get A and B $\displaystyle \int(2x-94)/(x^2+2x-63) dx = A/(x+9) + B/(x-7)$ $\displaystyle 2x - 94 = A(x+9)+B(x-7)$ How do I solve for A and B?
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Originally Posted by killasnake I need help with this Partial Fraction, I don't know how to get A and B $\displaystyle \int(2x-94)\frac(x^2+2x-63) dx = A/(x+9) + B/(x-7)$ $\displaystyle 2x - 94 = A(x+9)+B(x-7)$ How do I solve for A and B? i'm not sure what you're saying in your first line, but going off the second... let's call it equation (2) plug in x = -9 in (2) and solve for B then plug in x = 7 in (2) and solve for A
Oh okay Thank you, sorry I was having trouble writing the question in the math format.
Originally Posted by killasnake Oh okay Thank you, sorry I was having trouble writing the question in the math format. use \frac {}{} to get fractions. type the numerator in the first pair of {} and the denominator in the second pair so [tex]\frac {2x - 94}{x^2 + 2x - 63}[/tex] yields $\displaystyle \frac {2x - 94}{x^2 + 2x - 63}$
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