# Math Help - Limits in equation --->Infinity question

1. ## Limits in equation --->Infinity question

I've seen the Limit set to zero to solve the equation, but here I have infinity. How should I approach it?

$\lim_{x\to infinity}\frac{5x^2-17}{x^2+2}$

2. $\frac{{5x^2 - 17}}{{x^2 + 2}} = \frac{{5 - \frac{{17}}{{x^2 }}}}{{1 + \frac{2}{{x^2 }}}}$

3. Originally Posted by Plato
$\frac{{5x^2 - 17}}{{x^2 + 2}} = \frac{{5 - \frac{{17}}{{x^2 }}}}{{1 + \frac{2}{{x^2 }}}}$
So looking at this problem I should be able to "zero" out the denominators and my answer should just be $\frac{5}{1}=5$? Am I understanding correctly?

4. That is correct.