# Limits in equation --->Infinity question

• February 19th 2008, 11:37 AM
XIII13Thirteen
Limits in equation --->Infinity question
I've seen the Limit set to zero to solve the equation, but here I have infinity. How should I approach it?

$\lim_{x\to infinity}\frac{5x^2-17}{x^2+2}$
• February 19th 2008, 11:56 AM
Plato
$\frac{{5x^2 - 17}}{{x^2 + 2}} = \frac{{5 - \frac{{17}}{{x^2 }}}}{{1 + \frac{2}{{x^2 }}}}$
• February 20th 2008, 01:13 PM
XIII13Thirteen
Quote:

Originally Posted by Plato
$\frac{{5x^2 - 17}}{{x^2 + 2}} = \frac{{5 - \frac{{17}}{{x^2 }}}}{{1 + \frac{2}{{x^2 }}}}$

So looking at this problem I should be able to "zero" out the denominators and my answer should just be $\frac{5}{1}=5$? Am I understanding correctly?
• February 20th 2008, 01:38 PM
Plato
That is correct.