The problem is:
Use polar coordinates to find the volume of the given solid bounded by the paraboloid z=10-3x^2-3y^2 and the plane z=4.
Normally I can do these integrals, but what's throwing me off is that the region isn't bounded by the xy-plane, and the whole region lies above it. I'm not sure how to set it up. I know that it will be the double integral of 10-3r^2 and with theta going from 0 to 2pi and r going from 0 to ... I'm not sure. I'm really just confused. Thank you!