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Thread: calculus limits...trig

  1. #1
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    calculus limits...trig

    I can't seem to find out where to start or finish for this limit:

    Lim 1-cos 3x / cos(squared) 3x - 1
    x->0
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  2. #2
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    Krizalid's Avatar
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    Just factorise the bottom.
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  3. #3
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    calculus limits...trig

    sorry, that would make it a lot easier, but the bottom 3x was suppose to be a 5x. Thats what makes it so complicated. NEED HELP

    Lim 1-cos 3x / cos(squared) 5x - 1
    x->0
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  4. #4
    Math Engineering Student
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    \frac{{1 - \cos 3x}}<br />
{{\cos ^2 5x - 1}} =  - \frac{9}<br />
{{25}} \cdot \frac{{1 - \cos 3x}}<br />
{{9x^2 }}\left( {\frac{{5x}}<br />
{{\sin 5x}}} \right)^2 .

    The answer should be obvious from there.
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  5. #5
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    still need help

    that doesn't make it obvious. could you explain a little farther. Thanks
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