how do i integrate ... $\displaystyle x^3 . sqrt(x)$ i know that the integral of x^3 is x^4/4 and also the sqrt(x) is (x^3/2)/(3/2) but im not sure how to do them together... help please
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Originally Posted by b00yeah05 how do i integrate ... $\displaystyle x^3 . sqrt(x)$ i know that the integral of x^3 is x^4/4 and also the sqrt(x) is (x^3/2)/(3/2) but im not sure how to do them together... help please $\displaystyle x^3 \sqrt{x} = x^3 x^{1/2} = x^{7/2}$. Now use the usual rule for integrating $\displaystyle x^n$.
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