For this function,
determine the 4 stationary points in the region 0=< x <pi ; 0=< y <pi
I got these two eqn after partial diff for x and y
correct?
1 stationary points is (0,0), how can i find the other 3?
i got these 4 points (0,0) (pi,pi) (pi/2, pi) (pi,pi/2)
are these correct?
i think there is smthing wrong somewhere because i can't determine the 4 stationary points in the region 0=< x <pi ; 0=< y <pi
the answer stated 1 point is min, 2 are max and 1 is saddle.
Can anyone show me how to get? thanks
All of the points satisfy the equation, but as I think you noticed they are not all in the region.i got these 4 points (0,0) (pi,pi) (pi/2, pi) (pi,pi/2)
are these correct?
For we need either sin x = 0 or .
For we need either sin y = 0 or
Now you need to set up a pair of equations for each possible combination that will make both equations work:
sin x = 0
sin y = 0
sin x = 0
sin y = 0
Have a go at solving each of the pairs. The last one is a bit more difficult, but Peritus has already given you a hint.
let's examine the last two equations using the following formulas:
thus we get:
so we've got the following solutions:
after substituting the second solution in one of the first two equations I've given you we get:
thus this solution is obviously illegal:
substituting x = -y or x = y gives the same result namely:
can you continue...
Hi
after working out the solution i got
y = 54.73 x = 2(pi)+54.73 ------------for x=2(pi) +y eqn
the value or x is out of range
their is one simliar ans with c value out of range
others are -ve points........
wrong somewhere?
Help~~~~~~