how do you evaluate the following indefinite integrals?

(1 + √(2s-1)) /√(2s-1) ds

i know the answer to this is 1/2(1+√(2s-1))² + c but still don't get it. :S

and

(x²+3)^7 (x³-8x) dx

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- February 15th 2008, 07:29 AMTrueToHeartIndefinite integral?
how do you evaluate the following indefinite integrals?

(1 + √(2s-1)) /√(2s-1) ds

i know the answer to this is 1/2(1+√(2s-1))² + c but still don't get it. :S

and

(x²+3)^7 (x³-8x) dx - February 15th 2008, 08:36 AMPeritus

The answer is given in an equivalent form:

Quote:

(x²+3)^7 (x³-8x) dx