We want to calculate the limit limx→∞ 4x^2/Sqrt3x^4+2 (square root is for the whole bottom function) Rewrite The limit as as 4/sqrt3+g(x) (square root is for the whole bottom function)where g(x)=?
Follow Math Help Forum on Facebook and Google+
I know what the limit is when it goes towards infinity but just pointing out G(x) is confusing
$\dfrac{4x^2}{\sqrt{3x^4+2}} \cdot \dfrac{x^{-2}}{\sqrt{x^{-4}}}= \dfrac{4}{\sqrt{3+2x^{-4}}}$
Thank you! I see why I kept getting the wrong answer now, appreciate it!
View Tag Cloud