Originally Posted by
dankelly07 I have another problem with separable equations, can anyone help?
I need to know how I end up with PI and tan in the answers to these differential equations, its just not making much sense to me at the minute!
so I start with equation
dy/dx = 1+y^2/2+4x
which satisfies y(1) = 1
so this becomes
1/1+y^2 dy = 1/2+4x dx
??
Am I right so far?
then does the LHS
become
tan-1 and do you take the log of the RHS?
can anyone help me through the stages??
I have the solution
i just need to see how this works! especially with PI coming into it, how??
tan(PI/4+1/4ln(|2+4x/6|)).....
Any help would be gr8!