Is the answer to this problem, $\displaystyle \lim_{x \to 4}\frac{\frac{1}{m}-\frac{1}{4}}{m-4}$ equal to $\displaystyle \frac{-1}{16}$ or $\displaystyle \frac{1}{16}$?

I keep getting $\displaystyle \lim_{x \to 4}(\frac{m-4}{4m})(\frac{1}{m-4})$ which gives me $\displaystyle \frac{1}{16}$.

If the answer is $\displaystyle \frac{-1}{16}$, I'm probably making a simple mistake somewhere.